13/4y^2-13=0

Solution for 13/4y^2-13=0 equation:

13/4y^2-13=0


Domain of the equation: 4y^2!=0

y^2!=0/4

y^2!=√0

y!=0

y∈R


We multiply all the terms by the denominator


-13*4y^2+13=0

Wy multiply elements

-52y^2+13=0

a = -52; b = 0; c = +13;
Δ = b2-4ac
Δ = 02-4·(-52)·13
Δ = 2704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2704}=52$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-52}{2*-52}=\frac{-52}{-104}
=1/2
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+52}{2*-52}=\frac{52}{-104}
=-1/2
$